Practicing Success
A boy can jump to a height h on ground level. What should be the radius of a sphere of density d such that on jumping on it, he escapes out of the gravitational field of the sphere : |
\([\frac{4 \pi g h}{G d}]^{1/2}\) \([\frac{4 \pi G d}{3 g h}]^{1/2}\) \([\frac{3G d}{4 \pi g h}]^{1/2}\) \([\frac{3 g h}{4 \pi G d}]^{1/2}\) |
\([\frac{3 g h}{4 \pi G d}]^{1/2}\) |
When a boy jumps from a ground level up to height h then its velocity of jumping v = √2gh ... (i) and for the given condition this will become equal to escape velocity vescape : = \(\sqrt{\frac{2GM}{R}} \) = \(\sqrt{\frac{2 G}{R}\frac{4}{3} \pi R^3 d}\) ... (ii) From (i) and (ii) : \(\sqrt{2gh} = R \sqrt{\frac{2}{3} \pi G d}\) \(\Rightarrow R = [\frac{3}{4 \pi} \frac{gh}{dG}]^{1/2}\) |