The equation of tangent line to \(y = 2x^2+7\), which is parallel to the line \(4x-y+3 = 0\) is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → \(4x-y+5=0\)
The line \(4x - y + 3 = 0\) is \(y = 4x + 3\), with slope 4. Parallel lines have equal slopes, so the tangent has slope 4:
\( \displaystyle \frac{dy}{dx} = 4x \)
\(4x = 4\)
\(x = 1, \quad y = 2(1)^2 + 7 = 9\)
The tangent at (1, 9) with slope 4:
\(y - 9 = 4(x - 1)\)
\(y = 4x + 5\)
\(4x - y + 5 = 0\)
Note: This topic was not in the CUET 2026 syllabus.