For a linear programming problem, the feasible region is shown in the figure by shaded portion, then linear constraints are |
$3x+4y≤ 24,x + 2y ≤10,x ≥ 0,y ≥0$ $3x+4y≥24,x + 2y ≥ 10,x ≥0,y ≥0$ $3x+4y≥24,x + 2y ≤ 10,x ≥0,y ≥0$ $3x+4y ≤24,x + 2y ≥ 10,x ≥0,y ≥0$ |
$3x+4y ≤24,x + 2y ≥ 10,x ≥0,y ≥0$ |
The correct answer is Option (4) → $3x+4y ≤24,x + 2y ≥ 10,x ≥0,y ≥0$ Given: The shaded region is bounded by two lines and lies in the first quadrant. The lines are: 1. $x + 2y = 10$ 2. $3x + 4y = 24$ The feasible region lies below both lines and in the first quadrant (i.e., $x \geq 0,\ y \geq 0$). So, the inequalities are: $x + 2y \geq 10$ $3x + 4y \leq 24$ $x \geq 0$ $y \geq 0$ |