Answer & explanation
Correct answer: option 3
$\text{The average value of output current } I_{av} = 2/T \int_{0}^{T/2} I dt = \frac{2I_0}{\pi}$
Correct answer: option 3
$\text{The average value of output current } I_{av} = 2/T \int_{0}^{T/2} I dt = \frac{2I_0}{\pi}$