CUET Preparation Today
An electron moving with velocity of $5.4 × 10^6 m/sec$. What is the de-Broglie wavelength associated with them? $(h=6.63 × 10^{-34} J/s)$ |
0.135 Å 1.35 Å 13.5 Å 27.0 Å |
1.35 Å |
The correct answer is Option (2) → 1.35 Å The De-Broglie wavelength (λ) is - $λ=\frac{h}{P}=\frac{h}{mv}$ $=\frac{6.626×10^{-34}}{9.11×10^{-31}×5.4×10^6}$ $≃1.35Å$ |
