CUET Preparation Today
A capacitor charged from a 50 V d.c. supply is found to have charge of 10 μC. The capacitance of the capacitor would be: |
0.1 μF 0.2 μF 0.3 μF 0.4 μF |
0.2 μF |
The correct answer is Option (2) → 0.2 μF The relationship between the charge (Q), Voltage (V), and the Capacitance (C) of a capacitor is - $Q=C.V$ $⇒C=\frac{Q}{V}=\frac{10×10^{-6}}{50}$ $=0.2×10^{-6}F$ |
