A capacitor charged from a 50 V d.c. supply is found to have charge of 10 μC. The capacitance of the capacitor would be:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 0.2 μF
The relationship between the charge (Q), Voltage (V), and the Capacitance (C) of a capacitor is -
$Q=C.V$
$⇒C=\frac{Q}{V}=\frac{10×10^{-6}}{50}$
$=0.2×10^{-6}F$