A spherical planet has a mass Mp and Diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to :
Answer & explanation
Correct answer: option 3
g = \(\frac{GM}{R^2}\)
= \(\frac{GM_P}{(D_P/2)^2}\)
= \(\frac{4GM_P}{D_P^2}\)