If the diameter of a circle bisects each of the two chords of the circle, then both the chords:
Answer & explanation
Correct answer: option 2
L = mid-point of AB.
OL⊥AB [ Line joining the centre of a circle to the mid-point of a chord is perpendicular to the chord]
= ALO = 90∘
Similarly, ∠OMD = 90∘
Therefore, ∠ALO=∠OMD
But, these are alternate interior angles.
So, AB∥CD.