Which of the following statements is correct for a charged metallic shell?

The electric field intensity is zero inside the shell and decreases outside the shell as we move away from the shell.

The correct answer is Option (1) → The electric field intensity is zero inside the shell and decreases outside the shell as we move away from the shell. **

Inside a charged metallic shell, all excess charge resides only on the outer surface. Hence, the electric field inside the shell is zero because the net charge enclosed within any Gaussian surface inside the conductor is zero.

Outside the shell, the shell behaves as if its total charge were concentrated at its center. Therefore, the electric field intensity outside follows the inverse-square law:

$E = \frac{1}{4 \pi \varepsilon_0} \frac{Q}{r^2}$

This means that as the distance r increases, the electric field decreases.

Hence, inside the shell → E = 0, and outside the shell → E decreases as 1/r².