A is 20% more efficient than B. How much time will they working together take to complete a job which A alone could have done in 29 days ?
Answer & explanation
Correct answer: option 4
A is 20% more efficient than B i.e;
\(\frac{A}{B}\) = \(\frac{120}{100}\) = \(\frac{6}{5}\)
⇒ Efficiency (A = 6, B = 5),
A finishes work in 29 days,
therefore, total work = 6 x 29 = 174 .. (Efficiency × Days = Total work)
⇒ Time taken to complete the work by working together = \(\frac{174}{6+5}\)
= \(\frac{174}{11}\) days.