Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

The general solution of the differential equation $(1+y)dx-2xdy =0$ is :

Options:

$x=C(1+y)^2 $, where C is constant of integration

$x^2=C(1+y^2) $, where C is constant of integration

$x^2-y^2=C$, where C is constant of integration

$y=C+x^2y$, where C is constant of integration

Correct Answer:

$x=C(1+y)^2 $, where C is constant of integration