Practicing Success
Find $\frac{dy}{dx}$ where $y=\sin(\tan^{-1}e^x)$ |
$\frac{e^2x}{1+e^{2x}}\cos(\tan^{-1}e^x)$ $\frac{e^x}{1+e^{2x}}\cos(\tan^{-1}e^x)$ $\frac{e^x}{1+e^{2x}}\sin(\tan^{-1}e^x)$ $\frac{e^x}{1+e^{x}}\cos(\tan^{-1}e^x)$ |
$\frac{e^x}{1+e^{2x}}\cos(\tan^{-1}e^x)$ |
$\frac{dy}{dx}=\cos(tan^{-1}e^x)\frac{d}{dx}(\tan^{-1}e^x)=\frac{e^x}{1+e^{2x}}\cos(\tan^{-1}e^x)$ |