The value of the determinant
$Δ = \begin{vmatrix}sin 2\alpha & sin ( \alpha + \beta) & sin (\alpha + \gamma )\\sin (\beta + \gamma ) & sin 2 \beta & sin (\gamma + \beta)\\(sin \gamma + \alpha ) & sin ( \gamma + \beta ) & sin 2 \gamma \end{vmatrix},$ is
Answer & explanation
Correct answer: option 1
The correct answer is option (1) : 0
We have,
$Δ=\begin{vmatrix}sin \alpha & cos \alpha &0 \\sin \beta & cos\beta & 0\\sin \gamma & cos \gamma & 0\end{vmatrix}\begin{vmatrix}cos\alpha & sin\alpha &0 \\cos\beta & sin\beta & 0\\cos\gamma & sin\gamma & 0\end{vmatrix}$
$⇒Δ=0×0=0$