Number of ions produced on hydrolysis of Cr(NH₃)₄Cl₃ reacting with AgNO₃ to give 1 mole of AgCl, will be

2

Only 1 mol of AgCl is produced on reacting Cr(NH₃)₄Cl₃ with AgNO₃.

∴ Only one Cl^- is available after dissociation to react with AgNO₃.

Formula of coordination compound will be: [Cr(NH₃)₄Cl₂]Cl 

[Cr(NH₃)₄Cl₂]Cl → [Cr(NH₃)₄Cl₂]⁺ + Cl^-

[Cr(NH₃)₄Cl₂]Cl + AgNO₃ → [Cr(NH₃)₄Cl₂]NO₃ + AgCl