'A' can do a piece of work in 15 days, which 'B' can do in 10 days. 'B' worked at it for 8 days. 'A' can finish the remaining work in
Answer & explanation
Correct answer: option 2
Total work = LCM of 15, 10 = 30
Efficiency of A = 30/15 = 2
Efficiency of B = 30/10 = 3
B work in 8 days
⇒ 8 × 3
⇒ 24
Remaining work = 30 – 24 = 6
A will complete the remaining work = 6/2 = 3 days