CUET Preparation Today
Area lying in the first quadrant and bounded by the circle $x^2+y^2=4$ and the lines x = 0 and x = 2 is: |
$\pi$ $\frac{\pi}{2}$ $\frac{\pi}{3}$ $\frac{\pi}{4}$ |
$\pi$ |
The correct answer is Option (1) → $\pi$ Area of first quadrant from $x=0$ to $x=2$ ≡ area of quarters circle $=\frac{4\pi}{4}=\pi$ sq. units |
