Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

System of Particle and Rotational Motion

Question:

The coordinates of the centre of mass of the system shown in the figures are : 

Options:

(1.33L, 0.167L)

(0, 0)

(0.33L, 1.67L)

(L, L)

Correct Answer:

(1.33L, 0.167L)

Explanation:

Sum of masses = m + m + m + 3m = 6m

x-coordinate : (m x 0 + m x L + m x L + m x 2L)/6m = 1.33L

y-coordinate : (m x 0 + m x L + m x 0 + m x 0)/6m = 0.167L.