If tan θ + cot θ = 6, then find the value of $tan^2θ +cot^2θ$.
Answer & explanation
Correct answer: option 2
tan θ + cot θ = 6
On squaring both side
( tan θ + cot θ)² = 6²
tan² θ + cot² θ + 2 tan θ . cot θ = 36
{ tan θ = \(\frac{1 }{cot θ }\) }
tan² θ + cot² θ + 2 = 36
tan² θ + cot² θ = 34