Two friends Ronak and Sohan appear in an interview . There is 40% probability that Ronak can be selected and 66.66% probability that Sohan can be selected , then what is the probability that none of them get selected?
Answer & explanation
Correct answer: option 4
Ronak’s probability of getting selected = 40% = \(\frac{2}{5}\)
Sohan's probability of getting selected = 66.66% = \(\frac{2}{3}\)
The probability of Ronak not getting selected = 1 – \(\frac{2}{5}\) = \(\frac{3}{5}\)
The probability of Sohan not getting selected = 1 – \(\frac{2}{3}\) = \(\frac{1}{3}\)
The probability of both not getting selected = (\(\frac{3}{5}\)) (\(\frac{1}{3}\) ) = \(\frac{1}{5}\) = 20%
Hence, option D is correct.