Two friends Ronak and Sohan appear in an interview . There is 40% probability that Ronak can be selected and 66.66% probability that Sohan can be selected , then what is the probability that none of them get selected?

20%

Ronak’s probability of getting selected = 40% = \(\frac{2}{5}\)

Sohan's probability of getting selected = 66.66% = \(\frac{2}{3}\)

The probability of Ronak not getting selected = 1 – \(\frac{2}{5}\)  = \(\frac{3}{5}\)

The probability of Sohan not getting selected = 1 – \(\frac{2}{3}\) = \(\frac{1}{3}\)

The probability of both not getting selected = (\(\frac{3}{5}\)) (\(\frac{1}{3}\) ) = \(\frac{1}{5}\) = 20%

Hence, option D is correct.