Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If a + b = 10 and $\frac{3}{7}$ of ab = 9, then the value of $a^3 + b^3$ is :

Options:

350

270

370

360

Correct Answer:

370

Explanation:

If x + y  = n

then, $x^3 + y^3$ = n3 - 3 × n × xy

If a + b = 10

$\frac{3}{7}$ of ab = 9,

so, by solving ab = 21

then the value of $a^3 + b^3$ = 103 - 3 × 10 × 21

= $a^3 + b^3$ = 1000 - 630 = 370