Three mangoes and three apples are kept in a box. If two fruits are selected at random from the box, the probability that the selection will contain one mango and one apple is :

$\frac{3}{5}$

Total no. of fruits = 6

No. of mangoes = 3

No. of Apples = 3

No. of ways selecting 2 fruits $={ }^6 C_2$

No. of ways of selecting a Mango and on Apple $={ }^3 C_1 \times{ }^3 C_1$

(P) Probability = $\frac{{ }^3 c_1 \times{ }^3 c_1}{{ }^6 c_2}$

P = $\frac{3 \times 3 \times 2 ! \times 4 !}{6 !}$

P = $\frac{3 \times 3 \times 2}{6 \times 5}=\frac{3}{5}$