Four different numbers are given, out of which three are same in a certain way. Find the odd number that does not belong to the others?

(47, 6, 7) (17, 3, 4) (30, 9, 3) (68, 9, 7)

(30, 9, 3)

(A)  6 × 7 → 42 + 5 = 47          (B) 3 × 4  → 12 + 5 = 17 (C) 9 × 3  →  27 + 5 = 32   but 30 is given in the option ,thats why it is odd      (D) 9 × 7  →  63 + 5 = 68 So, option (C) is correct.