Practicing Success
A system consisting of two point charges 7 µC and -4 µC are placed at (-9, 0, 0) cm and (9, 0, 0) cm respectively. The electrostatic potential energy of the system is: |
- 0.7 J - 1.4 J - 3.6 J - 6.8 J |
- 1.4 J |
Distance between the two charges is 18cm. $ \Rightarrow U = \frac{kq_1q_2}{r} = \frac{ 9\times 10^9 \times -28\times 10^{-12}}{18\times 10^{-2}} = -1.4J$ |