The LCM of two multiples is 728 and the HCF is 13. If one of the numbers is 91, the other number is :
Answer & explanation
Correct answer: option 4
Let number be 13x and 13y respectively
LCM = 13xy
13xy = 728 (given)
xy = 56
∴ Possible pairs are (8, 7), (28, 2) (14, 4)
Only pair (8, 7) is satisfying
Numbers are = (13 × 8, 13 × 7 )
Given that one number is 91
So, other is 104