The LCM of two multiples is 728 and the HCF is 13. If one of the numbers is 91, the other number is :

117 65 65 104

104

Let number be 13x and 13y respectively LCM = 13xy 13xy = 728 (given) xy = 56 ∴ Possible pairs are (8, 7), (28, 2) (14, 4) Only pair (8, 7) is satisfying Numbers are = (13 × 8, 13 × 7 ) Given that one number is 91 So, other is 104