A box consists of 28 mangoes and 46 Bananas. How many bananas must be removed from the box so that 70% of the fruits in the box will be mangoes ?
Answer & explanation
Correct answer: option 3
Mangos = 28
Bananas = 46
ATQ,
If 70% of the fruits is mangoes then:
70% of total fruits = 28
\(\frac{7}{10}\) of total fruits = 28
Total fruits = 28 × \(\frac{10}{7}\) = 40
So,
Remaining 30% is bananas.
No. of bananas = 40 × \(\frac{3}{10}\) = 12
Therefore,
No. of bananas removed = 46 - 12 = 34