A box consists of 28 mangoes and 46 Bananas. How many bananas must be removed from the box so that 70% of the fruits in the box will be mangoes ?

34

Mangos = 28

Bananas = 46

ATQ,

If 70% of the fruits is mangoes then:

70% of total fruits = 28

\(\frac{7}{10}\) of total fruits = 28

Total fruits = 28 × \(\frac{10}{7}\) = 40

So,

Remaining 30% is bananas.

No. of bananas = 40 × \(\frac{3}{10}\) = 12

Therefore,

No. of bananas removed = 46 - 12 = 34