A box consists of 28 mangoes and 46 bananas. How many bananas must be removed from the box so that 70% of the fruits in the box will be mangoes?
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 34
Only bananas are removed, so the 28 mangoes stay. After the removal these 28 mangoes must be 70% of the fruits left in the box.
Total fruits left, of which 28 are 70%: \(\displaystyle28\times\frac{100}{70}=40\)
Bananas that may stay with the 28 mangoes: \(40-28=12\)
Bananas to be taken out of the 46: \(46-12=34\)