A die is thrown. If A is the event 'the number appearing is a multiple of 3 and B is the event 'the number appearing is even', then A and B are :

independent events

A and B are independent events as outcome of one doesn't depend upon other

$P(A) = \frac{2}{6}$ [as 3 and 6 are only multiples of 3

⇒ P(A) = $\frac{1}{3}$

P(B) = $\frac{3}{6}$ [2, 4, 6 are three even outcomes

P(B) = $\frac{1}{3}$

P(A ∩ B) = $\frac{1}{6}$  (6 is only even multiple of3)