The perimeters of ΔABC and ΔDEF are 39.6 cm and 26.4 cm, respectively, and ΔABC ∼ ΔDEF. What is the ratio of the areas of ΔABC and ΔDEF ? |
3 : 2 9 : 4 16 : 9 9 : 2 |
9 : 4 |
Point to be remembered = If two triangles are similar, the ratio of their area will be the square of the ratio of the length of their respective sides. The perimeter of ΔABC and ΔDEF = 39.6 and 26.4 cm According to the question ΔABC ~ ΔDEF = \(\frac{39.6}{26.4}\) = \(\frac{ ΔABC}{ ΔDEF}\) = \(\frac{3}{2}\) So, The ratio of the areas of ΔABC and ΔDEF = \(\frac{3^2}{2^2}\) = 9 : 4 |