The sum of degree and order of the differential equation \(\displaystyle\frac{d^3y}{dx^3}+2\left(\frac{d^2y}{dx^2}\right)+\left(\frac{dy}{dx}\right)+6y=0\), is
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 4
The order is the order of the highest derivative present, \(\frac{d^3y}{dx^3}\), so the order is 3.
The equation is a polynomial in the derivatives, and the highest derivative \(\frac{d^3y}{dx^3}\) appears to the power 1, so the degree is 1.
\(\text{order} + \text{degree} = 3 + 1 = 4\)