Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Inverse Trigonometric Functions

Question:

If $x=\frac{1}{5}$, the value of $\cos(\cos^{-1}x+2\sin^{-1}x)$ is:

Options:

$-\sqrt{\frac{24}{25}}$

$\sqrt{\frac{24}{25}}$

$-\frac{1}{5}$

$\frac{1}{5}$

Correct Answer:

$-\frac{1}{5}$

Explanation:

$\cos(\cos^{-1}\frac{1}{5}+2\sin^{-1}\frac{1}{5})=\cos[\cos^{-1}\frac{1}{5}+\sin^{-1}\frac{1}{5}+\sin^{-1}\frac{1}{5}]$

$\cos[\frac{π}{2}+\sin^{-1}\frac{1}{5}]=-\sin[\sin^{-1}\frac{1}{5}]=-\frac{1}{5}$