Practicing Success
If a fair coin is tossed 10 times, find the probability of : |
At least six heads. |
139/512 35/47 193/512 67/195 |
193/512 |
P(At least six heads) = P(X>=6) P(X>=6) = P(X=6) + P(X=7) + P(X=8) + P(X=9) + P(X=10) = 10C6(1/2)10 + 10C7(1/2)10 + 10C8(1/2)10 + 10C9(1/2)10 + 10C10(1/2)10 = 193/512 |