Area of the floor of a cubical room is 64 m2. The length of the longest rod that can be kept in the room is :
Answer & explanation
Correct answer: option 4
We know that,
Area of a floor = side2
The diagonal of a floor = a\(\sqrt {3}\)
Area of the floor of a cubical room = 64 m2.
a2 = 64
= a = 8 m
The length of the longest rod = 8 × \(\sqrt {3}\)= 8\(\sqrt {3}\) m.