The energy of satellite
Answer & explanation
Correct answer: option 4
Energy of the satellite E = $\frac{1}{2} m v^2-\frac{G M m}{r}$
$=\frac{1}{2} \times 500 \times(4000)^2-\frac{\left(6.67 \times 10^{-11}\right) \times\left(5.97 \times 10^{24}\right) \times 5000}{3.6 \times 10^7}$
= -1.5 × 1010 joule