Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Gravitation

Question:

The energy of satellite

Options:

1.6 × 107 joule

4.9 × 107 joule

0.2 × 107 joule

-1.5 × 1010 joule

Correct Answer:

-1.5 × 1010 joule

Explanation:

Energy of the satellite E = $\frac{1}{2} m v^2-\frac{G M m}{r}$

$=\frac{1}{2} \times 500 \times(4000)^2-\frac{\left(6.67 \times 10^{-11}\right) \times\left(5.97 \times 10^{24}\right) \times 5000}{3.6 \times 10^7}$

= -1.5 × 1010 joule