A car manufacturing plant produces Sedans and SUV's, using limited resources of steel, labour hours, and machine hours.

• Each Sedan requires 6 tons of steel, 10 labour hours and 8 machine hours.
• Each SUV requires 9 tons of steel, 15 labour hours and 12 machine hours.
• Plant has 600 tons of steel, 1200 labour hours and 1000 machine hours.
• Profit per Sedan is Rs. 50,000 and per SUV is Rs. 80,000

Formulate the problem as a LPP by defining decision variable and constraints.

$50,000x+80,000y$

The correct answer is Option (4) → $50,000x+80,000y$

$x$ → Total no. of Sedan

$y$ → Total no. of SUV

Optimization function, $Z=50,000x+80,000y$

and,

$6x+9y≤600,10x+15y≤1200,8x+12y≤1000$ [Constraints]