Match column I with column II
|
Column I (Element) |
Column (II) (Electrochemical equivalence) |
| A. Copper | p. 0.00112 |
| B. Silver | q. 0.000093 |
| C. Zinc | r. 0.000329 |
| D. Aluminium | s. 0.000339 |
[Atomic masses : Cu= 63.5, Ag= 108, Zn= 65.4, Al=27]
Answer & explanation
Correct answer: option 2
The correct answer is option 2. A-r, B-p, C-s, D-q.
|
Column I (Element) |
Column (II) (Electrochemical equivalence) |
| A. Copper | r. 0.000329 |
| B. Silver | p. 0.00112 |
| C. Zinc | s. 0.000339 |
| D. Aluminium | q. 0.000093 |
We know,
\(\text{Electrochemical equivalence (E.C.E.) = }\frac{\text{Equivalent weight}}{96500}\) ------ (i)
So, to find the electrochemical equivalence (E.C.E.), we need to find the equivalent weight of each element using the formula
\(\text{Equivalent Weight = }\frac{\text{Atomic mass of the element}}{\text{valency}}\)
A. \(Cu^{2+} (aq) + 2e^- \rightarrow Cu\)
\(∴ \text{Equivalent Weight = }\frac{63.5}{2} = 31.75\)
\(∴ \text{Electrochemical equivalence (E.C.E.) = }\frac{31.75}{96500} = 0.000329\)
Which corresponds to the value given in (r).
B. \(Ag^+ (aq) + e^- \rightarrow Ag\)
\(∴ \text{Equivalent Weight = }\frac{108}{1} = 108\)
\(∴ \text{Electrochemical equivalence (E.C.E.) = }\frac{108}{96500} = 0.00112\)
Which corresponds to the value given in (p).
C. \(Zn^{2+} (aq) + 2e^- \rightarrow Zn\)
\(∴ \text{Equivalent Weight = }\frac{65.4}{2} = 32.75\)
\(∴ \text{Electrochemical equivalence (E.C.E.) = }\frac{32.75}{96500} = 0.000339\)
Which corresponds to the value given in (s).
D. \(Al^{3+} (aq) + 3e^- \rightarrow Al\)
\(∴ \text{Equivalent Weight = }\frac{27}{3} = 9\)
\(∴ \text{Electrochemical equivalence (E.C.E.) = }\frac{9}{96500} =0.000093\)
Which corresponds to the value given in (q).
So, the correct answer is option (2) A-r, B-p, C-s, D-q.