The two parallel sides of a trapezium are 27 cm and 13 cm,respectively. If the height of the trapezium is 7 cm, then what is its area in $m^{2}$?
Answer & explanation
Correct answer: option 2
Dimensions of parallel sides of trapezium = 27 cm and 13 cm
Height of trapezium = 7 cm
27 cm = 0.27 m
13 cm = 0.13 m
7 cm = 0.07 m
So, Area of trapezium = [\(\frac{1}{2}\) (0.27 + 0.13)] × 0.07
= [\(\frac{1}{2}\) (0.40)] × 0.07
= 0.20 × 0.07 = 0.014 m2