The two parallel sides of a trapezium are 27 cm and 13 cm,respectively. If the height of the trapezium is 7 cm, then what is its area in $m^{2}$?

0.014

Dimensions of parallel sides of trapezium = 27 cm and 13 cm

Height of trapezium = 7 cm

27 cm = 0.27 m

13 cm = 0.13 m

7 cm = 0.07 m

So, Area of trapezium = [\(\frac{1}{2}\) (0.27 + 0.13)] × 0.07

= [\(\frac{1}{2}\) (0.40)] × 0.07

= 0.20 × 0.07 = 0.014 m²