When a number is increased by x%, by what percent the resultant should be decreased in order to get original number?

\(\frac{10x}{100+x}\)% \(\frac{x}{100+x}\)% \(\frac{100x}{100+x}\)% x%

\(\frac{100x}{100+x}\)%

Let Original number = 100 Increased number = 100 (+x%) = 100 + x To get the original number, increased number should be decreased by = x Therefore, ⇒ The number should be decreased by = \(\frac{x}{100+x}\) × 100 = \(\frac{100x}{100+x}\) %