The number of ions produced from one molecule of [Pt (NH₃)₅Br]Br₃ in the aqueous solution will be

4

The correct answer is (1) 4.

To determine the number of ions produced from one molecule of \([Pt(NH_3)_5Br]Br_3\) in an aqueous solution, we need to consider the dissociation of the complex and the dissociation of the \(Br_3^-\) ions.

The given complex is \([Pt(NH_3)_5Br]Br_3\).

When this complex dissolves in an aqueous solution, it dissociates as follows:
\([Pt(NH_3)_5Br]Br_3 \rightarrow [Pt(NH_3)_5Br]^{3+} + 3Br^-\)

 Thus the complex \([Pt(NH_3)_5Br]Br_3\) forms a total of 4 ions.