A tank is filled in 4 hours by three pipes A, B and C. The pipe C is  1\(\frac{1}{2}\) as fast as B and B is 3 times as fast as A. How many hours A will take to fill that tank?

34

ATQ, Efficiency:

C =  \(\frac{3}{2}\) B ⇒ 2C = 3B ⇒ B : C = 2 : 3

B =  3 A ⇒ A : B = 1 : 3

The ratio of efficiencies →

A : B : C = 2 : 6 : 9 = 17 (total)

Total work = 4 × 17 = 68

A will fill it in = \(\frac{68}{2}\) = 34 hours