A current of 5 A is flowing at 220 V in the primary coil of a transformer. If the voltage produced in the secondary coil is 2200 V and 50% of power is lost, then the current in the secondary coil will be
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 0.25 A
The output power of the transformer is the input power minus the power lost; here the efficiency is 50%.
\( P_{\mathrm{in}} = V_p I_p = 220 \times 5 = 1100\,\mathrm{W} \)
\( P_{\mathrm{out}} = 50\% \text{ of } 1100 = 550\,\mathrm{W} \)
\( \displaystyle I_s = \frac{P_{\mathrm{out}}}{V_s} = \frac{550\,\mathrm{W}}{2200\,\mathrm{V}} = 0.25\,\mathrm{A} \)