A bag contains 6 red, 4 blue and 10 white balls. A ball is picked from the bag at random. What is the probability that it is neither white nor blue?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \(\displaystyle\frac{3}{10}\)
A ball that is neither white nor blue must be red, so the probability asked for is the probability of drawing a red ball.
Total balls = 6 + 4 + 10 = 20
Red balls = 6
Probability \(=\displaystyle\frac{6}{20}=\frac{3}{10}\)