A bag contains 6 red, 4 blue and 10 white balls. A ball is picked from the bag at random What is the probability that it is neither white nor blue?

$\frac{20}{6}$ $\frac{3}{10}$ $\frac{2}{5}$ $\frac{1}{2}$

$\frac{3}{10}$

The correct answer is Option (2) → $\frac{3}{10}$