A bag contains 6 red, 4 blue and 10 white balls. A ball is picked from the bag at random What is the probability that it is neither white nor blue?

$\frac{3}{10}$

total balls= 20

red balls = 6

blue= 4

white balls= 10

if it is not white nor blue this means it will be a red ball

so probability of getting red ball is = 6/20 or 3/10

The correct answer is Option (2) → $\frac{3}{10}$