CUET Preparation Today
A bag contains 6 red, 4 blue and 10 white balls. A ball is picked from the bag at random What is the probability that it is neither white nor blue? |
$\frac{20}{6}$ $\frac{3}{10}$ $\frac{2}{5}$ $\frac{1}{2}$ |
$\frac{3}{10}$ |
total balls= 20 red balls = 6 blue= 4 white balls= 10 if it is not white nor blue this means it will be a red ball so probability of getting red ball is = 6/20 or 3/10 The correct answer is Option (2) → $\frac{3}{10}$ |
