Find the mean proportion of \(\frac{1}{9}\) and \(\frac{1}{121}\) .
Answer & explanation
Correct answer: option 4
Mean proportion of a and b = \(\sqrt {a × b }\)
⇒ Mean proportion = \(\sqrt {\frac{1}{9} × \frac{1}{121}}\)
= \(\frac{1}{3 × 11}\) = \(\frac{1}{33}\)