CUET Preparation Today
Find the mean proportion of \(\frac{1}{9}\) and \(\frac{1}{121}\) . |
\(\frac{1}{20}\) \(\frac{1}{16}\) \(\frac{1}{35}\) \(\frac{1}{33}\) |
\(\frac{1}{33}\) |
Mean proportion of a and b = \(\sqrt {a × b }\) ⇒ Mean proportion = \(\sqrt {\frac{1}{9} × \frac{1}{121}}\) = \(\frac{1}{3 × 11}\) = \(\frac{1}{33}\) |
