An electron gun emits $3 \times 10^{16}$ electrons per second. What electric current does this correspond to? |
4.8 A 1.9 A 4.8 µA 4.8 mA |
4.8 mA |
The correct answer is Option (4) → 4.8 mA To calculate the electric current corresponding to the emission of electrons - $I=n.e$ $I=(3×10^{16})×(1.6×10^{-19})$ $=4.8mA$ |