An electron gun emits $3 \times 10^{16}$ electrons per second. What electric current does this correspond to?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 4.8 mA
To calculate the electric current corresponding to the emission of electrons -
$I=n.e$
$I=(3×10^{16})×(1.6×10^{-19})$
$=4.8mA$