If a sinA + b cosA = c, then a cosA - b sinA is equal to:

Given :-

a sinA + b cosA = c

We know,

If a sinθ + b cosθ = c

Then , a cosθ - b sinθ = $\sqrt{a^2+b^2-c^2}$

Similarly,

a cosA - b sinA

= $\sqrt{a^2+b^2-c^2}$