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If a sinA + b cosA = c, then a cosA - b sinA is equal to: |
$\sqrt{a^2-b^2-c^2}$ $\sqrt{a^2+b^2-c^2}$ $\sqrt{a^2+b^2+c^2}$ $\sqrt{a^2-b^2+c^2}$ |
$\sqrt{a^2+b^2-c^2}$ |
Given :- a sinA + b cosA = c We know, If a sinθ + b cosθ = c Then , a cosθ - b sinθ = $\sqrt{a^2+b^2-c^2}$ Similarly, a cosA - b sinA = $\sqrt{a^2+b^2-c^2}$ |
