In a party 23 persons take their seats at a round table. The odds against two particular persons sitting together are:
Answer & explanation
Correct answer: option 1
23 persons can sit at a round table in 22! ways.
The number of ways in which two particular persons sit together=21!× 2!
∴ Probability that two particular persons sit together $=\frac{21!× 2!}{22!}=\frac{1}{11}$
Hence, odd against two particular persons sit together are 10 : 1. [∵ odd against =$P(\overline{A}): P(A)]$