A circle is inscribed in a triangle ABC. It touches the sides AB, BC and AC at the points R, P and Q respectively. If AQ = 3.5 cm, PC = 6.5 cm and BR = 8 cm, then the perimeter of the triangle ABC is?
Answer & explanation
Correct answer: option 1
With the help of Tangent property
AQ = AR = 3.5 cm
BR = BP = 8 cm
PC = CQ = 6.5 cm
Perimeter = AB + BC + CA
= AR + RB + BP + PC + CQ + AQ
= 3.5 + 8 + 8 + 6.5 + 6.5 + 3.5 = 36 cm