If (a + b) : (b + c) : (c + a) = 5 : 6 : 7 and 4a + 3c = 48, then c is equal to ?

6 8 12 9

8

a + b = 5R, b + c = 6R, c + a = 7R Adding all of above, we get: 2(a + b + c) = 18R (a + b + c) = 9R      ...............(i) b + c = 6R   ...........(ii) (i) - (ii) a = 3R, similarly b = 2R,  c = 4R Now, ⇒  4a +  3C = 48 ⇒  (4 × 3R) +  (3 × 4R) = 48 ⇒  12R  + 12R = 48 ⇒  24R = 48 ⇒  1R = 2  Here, c = 4R = 4 × 2 = 8