Practicing Success
Practicing Success
CUET Preparation Today
In a ΔABC, ∠A = 90°, if BM and CN are two medians, $\frac{BM^2+CN^2}{BC^2}$ is equal to: |
$\frac{3}{5}$ $\frac{4}{5}$ $\frac{5}{4}$ $\frac{3}{4}$ |
$\frac{5}{4}$ |
