CUET Preparation Today
If A is an invertible matrix of order 3 and the determinant of A is 9, then the determinant of $A^{-1}$ is: |
1 9 0 1/9 |
1/9 |
The correct answer is Option (4) → 1/9 Given $|A|=9$ Property of determinants $|A^{-1}|=\frac{1}{|A|}$ $|A^{-1}|=\frac{1}{9}$ The determinant of $A^{-1}$ is $\frac{1}{9}$. |
