Which of the following interchange of numbers and mathematical signs would make the given equation correct ?

28 ÷ 7 × 10 ÷ 5 - 20 = 5 

5 and 10 , + and ÷

Given equation;  28 + 07 x 10 ÷ 5 - 20 = 05

According to the que, after interchanging of numbers and mathematical signs;

So,

--> Option 01= 10 and 20, x and +

28 × 7 + 20 ÷ 5 - 10 = 5

28 × 7 + 4 - 10 = 5

196 + 4 - 10 = 5

200 - 10 = 5

190 \(\neq \)5 (LHS \(\neq \)RHS)

--> Option 02= 5 and 20, - and +

28 + 7 × 10 - 20 ÷ 5 = 20

28 + 7 × 10 - 4 = 20

28 + 70 - 4 = 20

98 - 4 = 20

94 \(\neq \)20 (LHS \(\neq \)RHS)

--> Option 03= 7 and 28, x and ÷

7 + 28 ÷ 10 × 5 - 20 = 5

7+2.8x5-20=5

7 + 14 - 20 = 5

18 - 20 = 5

-2 \(\neq \)5 (LHS \(\neq \)RHS)

--> Option 04= 5 and 10, + and ÷

28 ÷ 7 × 5 + 10 - 20 = 10

4 × 5 + 10 - 20 = 10

20 + 10 - 20 = 10

30 - 20 = 10

10 = 10 (LHS = RHS)