A 10 V battery of negligible internal resistance is being charged by a 200 V battery with a resistance of 38 Ω in series. The value of the current in the circuit is

5 A

The correct answer is Option (2) → 5 A

Effective voltage driving the current:

$V = 200 - 10 = 190 \; \text{V}$

Series resistance: $R = 38 \; \Omega$

Current: $I = \frac{V}{R} = \frac{190}{38} = 5 \; \text{A}$